x^2+3x=250

Solution for x^2+3x=250 equation:

x^2+3x=250

We move all terms to the left:

x^2+3x-(250)=0

a = 1; b = 3; c = -250;
Δ = b2-4ac
Δ = 32-4·1·(-250)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1009}}{2*1}=\frac{-3-\sqrt{1009}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1009}}{2*1}=\frac{-3+\sqrt{1009}}{2}
$